taken from https://stackoverflow.com/questions/5506888/permutations-all-possible-sets-of-numbers
for my note
python https://docs.python.org/2/library/itertools.html#itertools.permutations
I've ported the Python itertools code listed here (using generators). The advantage over the solutions posted so far is that it allows you to specify r (permutation size).
function permutations($pool, $r = null) {
$n = count($pool);
if ($r == null) {
$r = $n;
}
if ($r > $n) {
return;
}
$indices = range(0, $n - 1);
$cycles = range($n, $n - $r + 1, -1); // count down
yield array_slice($pool, 0, $r);
if ($n <= 0) {
return;
}
while (true) {
$exit_early = false;
for ($i = $r;$i--;$i >= 0) {
$cycles[$i]-= 1;
if ($cycles[$i] == 0) {
// Push whatever is at index $i to the end, move everything back
if ($i < count($indices)) {
$removed = array_splice($indices, $i, 1);
array_push($indices, $removed[0]);
}
$cycles[$i] = $n - $i;
} else {
$j = $cycles[$i];
// Swap indices $i & -$j.
$i_val = $indices[$i];
$neg_j_val = $indices[count($indices) - $j];
$indices[$i] = $neg_j_val;
$indices[count($indices) - $j] = $i_val;
$result = [];
$counter = 0;
foreach ($indices as $indx) {
array_push($result, $pool[$indx]);
$counter++;
if ($counter == $r) break;
}
yield $result;
$exit_early = true;
break;
}
}
if (!$exit_early) {
break; // Outer while loop
}
}
}
It works for me, but no promises! Example usage:
$result = iterator_to_array(permutations([1, 2, 3, 4], 3));
foreach ($result as $row) {
print implode(", ", $row) . "\n";
}
from https://stackoverflow.com/a/43307800/6125958